khp + naoh
(1.91e-3)(204.224) / .3907 x 100 = 99.88%, Then take average of all three to rfind the final %KHP: .4924g / 204.224 g/mol = 2.41e-3 mol KHP / .0254L = .0945 M NaOH, Flask#3: Change ), You are commenting using your Google account. This would weight 1.54375 x 10^-3 x 204.224 = 0.3153 g How do I find the percentage of KHP in a sample with the following information: Weighed out a certain amount of KHP (MW=204.22g/mol) into each Erlenmeyer flask: Added 50mL of distilled water to each of the flask. Thanks a lot for all the help thus far by the way! From the information you have given, it appears you were given the molarity of NaOH to allow you to calculate the % composition of KHP, I can't say anything about the concentration of NaOH. Introduction Question: Question 9 2 Pts KHP (aq) + NaOH(aq) — NaKHP (aq) + H2O (1) Trial V: (mL) V+(mL) 47.25 1 35.81 2 3 A Student Masses Out 1.033 Grams Of KHP, Which Is Dissolved In 25.00 ML Of DI Water. You will use this primary standard to determine the concentration of a sodium hydroxide solution. Most indicators are intensely colored so a dilute solution is sufficient for the titration. This KHP Solution Is Titrated With NaOH, As Shown In The Equation Above. The structure of KHP is shown below: 2. I doubt it could be 50% - 50g/100ml would be 500g/L - this would be about 12-13M - it is very unlikely that you would be provided a 50% solution as this would be very corrosive and is not suitable as a standard as it readily absorbs CO2. Sodium hydroxide is hygroscopic and absorbs water from the air when you place it on the balance for massing. (0.0625M NaOH)(24.7mL) / 1000mL = 1.54e-3 NaOH, And if it's a 1:1 then: It is water soluble and available in high purity. ( Log Out / Introduction Sodium hydroxide is hygroscopic and absorbs water from the air when you place it on the balance for massing. If exactly equivalent amounts of acid or base are used so that neither reactant is present in excess the solution is said to be at the equivalence point. And then from there I find the moles of NaOH first? The reaction shifts to the right. The volumetric analysis allows for the calculation of the unknown amount or concentration by a reaction with a known amount of reagent. A buret filled with the titrant (NaOH solution) is used to measure the volume of NaOH solution added to the known amount of acid in a flask. Is the molarity for NaOH correct? Objective therefore number of moles of KHP is 1.0874/(39.1+1+31) =0.015mol. A 0.8234-g sample of "KHP" required 38.76 mL of NaOH for titration to the phenolphthalein endpoint. So to find the molarity of NaOH from part2 of my experiment I did: Flask#1: Introduction Sodium hydroxide is hygroscopic and absorbs water from the air when you place it on the balance for massing. Potassium Hydrogen Phthalate ( referred in the experiment as KHP) was a brittle, white, crystalline substance. Then the molarity was determined from this titration and the value used to determine the percentage composition of KHP in another experiment. The indicator is a weak acid (or base) itself and reacts with some of the titrant to produce the color change The endpoint occurs when all the acid has been neutralized and the solution composition changes suddenly from excess acid to excess base. The titrations yielded an average concentration of 27.99% KHP in unknown sample. find the percentage of KHP in a sample by titration with NaOH, (M NaOH)(mL titrated) / 1000mL = mol NaOH, finding Ksp for a solution where solubility is known, Calculate the concentration of ion in the given solution using Ksp, determining if a reaction forms a precipitate when two solutions are mixed, Calculate [Ag+] in this saturated solution of Ag2SO4, Find the solubility product when solubility is given, calculate the solubilitry constant (Ksp) for cupric hydroxide Cu(OH)2, Ksp solubility product constant at 25C for AgCl, Find the molar concentration of F- ions if given Ksp for CaF2 and [Ca2+] ionsca. The crystals required intense stirring before it could dissolved in water. These two atoms combine with the oxygen from the NaOH to form H2O, which is the chemical formula for water. When KHP and a base a reacted, a neutralization reaction occurs that is represented by the following equation: What is the exact molarity of the NaOH solution? (2.40e-3)(204.224 g/mol KHP) / 0.5016g x 100 = 97.7%, Flask#2: Because of its high purity, you can determine the number of moles of KHP directly from its mass and it is referred to as a primary standard. Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. We made the 50% NaOH solution by boiling ~1000mL of tap water for 1.5 hours to get rid of the CO2. ( Log Out / The structure of KHP and its pKa value are also shown in Table 1 BUT since that's the case, do I find the new molarity of NaOH using my unknown-KHP masses? ( Log Out / The reaction can be considered to proceed completely to the right. This can then be compared to the NaOH to find the number of moles NaOH has.. Using flask 1 details, moles NaOH = 0.0247 x 0.0625 = 1.54375 x 10^-3 In the first part of the experiment using KHP as the primary standard I found the molarity of my NaOH to be .0580M, but I was hesitant to use that molarity for part2 of the experiment since the amount of KHP we used was .2-.3g less (and it was also an unknown-KHP) and so I thought it would affect the molarity from that. If the molarity of the NaOH was 0.0625M, this is what must be used in the calculations. Change ), Crystallization and Purification Melting Point and Boiling Point of Naphthalene, Synthesis of Cyclohexene from Cyclohexanol by Acid Catalyzed E1 Elimination, Standardization of a NaOH Solution with Potassium Hydrogen Phthalate (KHP). .3907g / 204.224 g/mol = 1.913e-3 mol KHP / .01972L = .0970 M NaOH, Then take the average to find M NaOH: This was an experiment I did in class. Since the indicator reacts with some of the titrant and the indicator may not change at the exact pH of the equivalence point, a small error in introduced in the titration. NaOH +KHP -----> H2O + KNaP. With a standard deviation being 2.41 the experiment concluded with 95% confidence that the KHP concentration in the unknown sample measures between 25.58% and 30.4%. [(1.54e-3)(204.224 g/mol) / sample weight] x 100 = gives % of KHP. I expect that there would have been a dilution from the concentrated NaOH solution and the resulting solution then standardised vs a suitable primary standard (HCl, H2SO4 oxalic acid or KHP). The net ionic equation is: What is the exact molarity of the NaOH solution? An acid-base titration is a procedure used to compare the amount (moles) of acid in one sample with the amount (moles) of base in another. Potassium hydrogen phthalate (KHP) is a widely used primary standard (functioning as a mono- protic acid) for acid/base titrations. The resultant Acidic solution was transparent, with a small amount of undissolved granules of KHP.
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